Code #1

Observations

Go through your usual cipher routine, a simple one

Spoiler

Rot 16 gives

kgreifisubstratethtwtwhw

Split into the passcode format

kgr ei fi substrate th tw tw hw

kgr85substrate322hw

Code #2

Observations

15 characters with the right amount of numbers for a valid passcode

Spoiler

Make a 3×5 grid

`v`	`m`	`6`
`6`	`a`	`o`
`m`	`g`	`3`
`o`	`i`	`5`
`3`	`c`	`m`

Reverse rows 2 & 4

`v`	`m`	`6`
`o`	`a`	`6`
`m`	`g`	`3`
`5`	`i`	`o`
`3`	`c`	`m`

Read going down from the upper left V

vom53magic663om

Code #3

Observations

Those letters fall in a very specific range

Spoiler

Convert letters to numbers

13 13 12 21 11 12 11 11 3 21 3 22 13 12 11 21 12 13 23 12 22 21 11 12 13 22 11 21 1 3 21 22 11 21 22 11 11 22 13 22 12 24 11 22 11 12

No zeros and all in the lower digits. The sum of all digits is 144 which can be divided by 8, RLE is the way to go

01110111 01100101 01101010 00110111 00110111 01101001 01101110 01110110 01100101 01101110 01101001 01110010 01101001 00110101 00110111 00110110 01111010 01101011

Convert binary to Ascii

wej77inveniri576zk

Code #1

Observations

Code #2

Observations

Code #3

Observations

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