Count how many numbers you have and why that matters
Spoiler
If you get all three codes together you have 15 numbers and the rest is all letters. 15 numbers is exactly what you need for 3 passcodes.
ekh9clutc78xqj6iraro38dsg22myre84uub99appi777yrh
A 12×4 grid reveals interesting things
e
k
h
9
c
l
u
t
c
7
8
x
q
j
6
i
r
a
r
o
3
8
d
s
g
2
2
m
y
r
e
8
4
u
u
b
9
9
a
p
p
i
7
7
7
y
r
h
In the first column you can see a good start for a passcode. Then in other columns you can see “cryp” which could lead to the keyword crypto. Let’s rearrange the columns as if we were using a skip of 3: 1, 4, 7, 10, 2, 5, 8, 11, 3, 6, 9, 12
e
9
u
7
k
c
t
8
h
l
c
x
q
i
r
8
j
r
o
d
6
a
3
s
g
m
e
u
2
y
8
u
2
r
4
b
9
p
7
y
9
p
7
r
a
i
7
h
Read going down from the upper left E
eqg99impure778uykj29crypto878durh62alaric347xsbh
Still need a bit of tweaking but let’s split the string in 3 equal parts
