16 characters, too many numbers for a straight valid passcode.
[hint]New keyword[/hint]
Make a 4×4 grid
9
u
2
h
o
a
t
e
r
5
0
9
c
9
5
7
Read going up from the lower left C
cro995au50t279eh
Let’s split things up a bit
cro99 5au50t 279eh
In the keyword section, convert the numbers to roman numerals
cro99vault279eh
That’s a new keyword that you need to add to your list
Code #2
Observations
If you reverse the code you could get a good start for a prefix and the last few characters for a suffix. So far the solution has not be found. Will update the post once it is found.
**** Post update thanks to agents @komasanmoge & @punchingcat
Make a 6×4 grid
i
i
8
s
c
j
g
m
2
o
i
s
k
r
7
7
9
i
4
o
3
e
f
o
Read rows 1 and 3 going left
jcs8iii977rk
Convert roman numeral iii to number
jcs83977rk
Read rows 2 and 4 going left
sio2mgofe3o4
Searching on Google gives the chemical compound SiO2 MgO Fe3O4 as being Obsidian
jcs83obsidian977rk
Code #3
Observations
Symbols seem to split but the full solution hasn’t been found yet.
**** Post update thanks to agents @komasanmoge & @yushi2000
Split at symbols and convert symbols to their respective numbers on the keyboard
1722
3235
4039
4860
5660
6974
7791
8199
8707
9221
11325
From the following number subtract the preceding number
