34 letters that seem to be in the range of R to Y. Paired that would be 17 characters which is good for a passcode.
Let’s start by making pairs
sv su ss ux ux rx tq rv rx tq tu rv uu uz uy ru sr
Notice how lots of pairs start with S and look at where numbers should fall, they all start with U. Knowing that in Ascii numbers starts with either 4 or 5, how can we make U=5? Well U is 5 letters before Z.
To make things a bit easier Atbash the string
he hf hh fc fc ic gj ie ic gj gf ie ff fa fb if hi
Convert letters to numbers, a=0
74 75 77 52 52 82 69 84 82 69 65 84 55 50 51 85 78
Convert decimal to Ascii
30 letters, no specific range. Let’s go through the cipher routine.
[hint]Don’t think this cipher has been used since the passcode format change. A might help you :p[/hint]
Atbash, ROT, morse, transposition didn’t give any good results. Next option would be Vigenere but now that the passcode format doesn’t start with numbers it’s a bit harder to brute force. But… there is always Vigenere Autokey with A has the passphrase.
Note that they only way we knew that is that it has been used in the past.
Mix of letters and numbers but that “,” should hint you on what cipher to use
[hint]You’ll need to look at the tool at the tip of your fingers in a different way[/hint]
With that comma it hints to a classic keyboard mirror cipher. We’ve had a few in the past where it was 1=0, q=p, a=; and z=/ but this one is the other way round: 1=z q=a.