Different groups of letters in the range of C to J.
[hint]You might want to phone a friend[/hint]
Spoiler
The fact that only H and J have groups of 4 sort of gives it away. Think of changing the letters to numbers (A=0) H and J would be 7 and 9 which are the only two numbers on a phone keypad to have 4 corresponding letters.
Convert letters to numbers (A=0) then convert from phone keypad cipher
8
T
9
W
666
O
2
A
8
T
44
H
333
F
666
O
88
U
777
R
7
P
44
H
444
I
555
L
555
L
444
I
7
P
7777
S
9999
Z
7777
S
444
I
99
X
66
N
333
F
444
I
888
V
33
E
666
O
2ath4phillipsz6n5o
Code #2
Observations
Good code format, go through your normal decoding routine
Spoiler
Atbash the letters and numbers
3ofz7thenh8o7r
“Then” is not a valid keyword. The cipher used was Atbash so the reverse of Then would be Now
3ofz7nowh8o7r
Code #3
Observations
32 numbers which would make 16 pairs.
[hint] Dec or ceD ?[/hint]
Spoiler
16 pairs would make for a 6 letter keyword code. Make pairs:
75 56 56 38 25 38 96 56 28 76 27 76 35 07 75 87
Some values are too low to be valid Ascii letters or numbers. Look at where the numbers in the code should fall, notice how they all end with 5 (75, 25, 35, 75). We know that characters 2 to 9 in Ascii are 50 to 57 in decimal. Lets reverse each pairs
