All letters, many ciphers can be used. I usually go through my sequence: Atbash, ROT, Morse, Vigenere, Rectangles…

No luck

[hint]Well in this case, you win some, you loose some!!!

[/hint]

Since none of the usual cipher worked I tried to split the code to see if somethings were matching. Niantic usually use three letters for word so here is how I made the split: uvp gtq ghw dckbblcfua m jmf f uvp e

Looking at the number positions, uvp comes up twice.
Now to find how can this sequence of letters become TWO, THR, FOU, FIV, SIX, SEV, EIG or NIN

The only answer was that it had to be TWO by alternating ROT-1 & ROT+1: -+-+-+-+-+-+-+-+-+-+-+-+-+-+
uvpgtqghwdckbblcfuamjmffuvpe
twohsrfiveblackdevzninegtwof

2hsr5blackdevz9g2f

Code #2

Observations

Numbers, letters and symbols, all in pairs. 24 of them.

[hint]Think of a cipher that uses 3 type of characters and has to be divisible by 4 to make it work good.

[/hint]

The fact that the numbers fall in the decimal to Ascii range can’t be coincidence. Then looking at the letters, they range from a to j or 0 to 9. Symbols can also be converted to numbers. Everything is pointing to a decimal to Ascii conversion.

Start by making pairs

79 71 *$ fe 89 84 82 *$ ^% 87 fd &% ^& fa fh ej ^^ 71 81 ei ^* &$ ^* ei

Convert everything to numbers, a=0 and symbols convert to their number position on the keyboard

Remember that strings starting with N or O can be Base64 to Ascii. Now we need to know which are lowercase and uppercase. From the original string, whatever was a pair of symbols needs to be converted to lowercase 79 71 *$ fe 89 84 82 *$ ^% 87 fd &% ^& fa fh ej ^^ 71 81 ei ^* &$ ^* ei O G t 6 Y T R t a W 5 k c 2 9 1 b G Q 0 d j d 0 OGt6YTRtaW5kc291bGQ0djd0

Convert Base64 to Ascii

8kza4mindsould4v7t

Need a substitution for Mind Soul, it usually is Body Mind Soul.

8kza4bodyd4v7t

Code #3

Observations

All numbers, nothing really stands out.

[hint]If you are thinking numbers to letters, you are on the right path. Just with a different twist.

[/hint]

Niantic used a common cipher but with a different approach to make it a bit more harder to solve.

I first started by making pairs 05 08 06 02 18 07 01 04 00 00 00 13 08 00 04 00 03 12 07 01 11 04 01 06 00 00 02 11 01 23 12 00 04 09 05 03 14 07 06 12 03 05 06 03

Seeing that 05 08 at the beginning I thought numbers to letters (a=0) FIGCSHBEAAANIAEADMHBLEBGAACLBXMAEJFDOHGMDFGD

That just didn’t make any sense and was way to long to convert to a code.

I then started playing with different ways of grouping the numbers. Groups of 4 gave me 22 groups which could lead to a code if numbers are spelled. 0508 0602 1807 0104 0000 0013 0800 0400 0312 0701 1104 0106 0000 0211 0123 1200 0409 0503 1407 0612 0305 0603

My first instinct was to just add up the numbers in each groups (0508=0+5+0+8=13). Seemed good since the first two set gave 13 & 8 which gave NI. But the rest just didn’t make sense.

Then I started adding pairs in each groups of 4 (0508=05 + 08=13) and got